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Assertion Exception handling

 
prashanth kumar
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Hello All,
How can following code compile?
Iam asking this because,this code block is trying to catch an Exception which is never thrown[AssertionError is NOT a child of Exception].But code still compiles

Why is that?

Many Thanks

 
Henry Wong
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The Exception class is also the base class for the RuntimeException class. The compiler is allowing the Exception here because it can't tell if it "is trying to catch an Exception which is never thrown" -- it could be an unchecked exception that is caught.

Henry
 
prashanth kumar
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Thanks for the clarification.
This means that a called method[even if it doesnt throw any chcecked exceptions] can always be there in try-catch block of calling method with "Exception" catch, since RunTimeException is a subclass of Exception.
Ex:


I tested this and it works.

Thanks Again
Prashanth
 
Ramu Malur S R
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Hi Prashanth,

Including any code in the try block does not mean that the code should throw an exception.

Compiler only cares about checked Exceptions and since AssertionError is a runtime Error(not an exception, it does not even come under Exception heirarchy ), the compilation proceeds even if you don't deal with it.

Moreover it is not a good practice to handle Assertion errors(As they can be disabled when the code compiles or runs), it is meant to use only during development not during deployment.

- Ramu
 
wise owen
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