On thread calling

[Naveen Zed]

code given in phazam today is

  What will happen when you attempt to compile and run the following code? 
public class LovesBlind implements Runnable{
    String sName="";
    public static void main(String argv[]){
LovesBlind lb = new LovesBlind();
lb.sName="1";
lb.run();
LovesBlind lb2 = new LovesBlind();
lb2.sName="2";
new Thread(lb2).start();
    }
    public void run(){
System.out.println("run"+sName);
 
    }
}  

and the answars given are
1. Compile time error, the line that creates a new Thread is faulty.
2. Compilation and output of run1 and run2, but the order cannot be determined.
3. Compilation and output of run1 followed by run2
4. Compilation and output of run2 followed by run1

My problem is, Why the answar is not 2?Can't be main thread interrupted and the chance given to the other thread (started with lb2) ,before the run() method print run 1.Why there is no probability of printing run2 before run1?

[prashanth kumar]

Originally posted by Naveen Zed:
code given in phazam today is

  What will happen when you attempt to compile and run the following code? 
public class LovesBlind implements Runnable{
    String sName="";
    public static void main(String argv[]){
LovesBlind lb = new LovesBlind();
lb.sName="1";
lb.run();
LovesBlind lb2 = new LovesBlind();
lb2.sName="2";
new Thread(lb2).start();
    }
    public void run(){
System.out.println("run"+sName);
 
    }
}  

and the answars given are
1. Compile time error, the line that creates a new Thread is faulty.
2. Compilation and output of run1 and run2, but the order cannot be determined.
3. Compilation and output of run1 followed by run2
4. Compilation and output of run2 followed by run1

My problem is, Why the answar is not 2?Can't be main thread interrupted and the chance given to the other thread (started with lb2) ,before the run() method print run 1.Why there is no probability of printing run2 before run1?

When you say,"lb.run();",you are NOT creating a new thread but you are making a method call...And since its executing in the same thread,its a synchronous method call...so main thread wont continue,till the method returns..
And hence the answer..

Hope This helps

[Naveen Zed]

Thank you, I understood the situation.