Result of the Code

[RAMA KRISHNA AALLA]

What is result of the below code for
command line-invocation java A 1 2 3

public class A
{
public static void main(String [] args)
{
String [][] array = new String[2][2];
int x;
array[0]=args;
x=array.length;
for(int y=0;y<x;y++)
{
System.out.println(" "+array[0][y]);
}
}
}

A. 0 0
B. 1 2
C. 0 0 0
D. 1 2 3
E. Compilation fails
F. An Exception is thrown at runtime

[Barry Gaunt]

Have you compiled and run the code yourself? If so, then what do you not understand?

Oh, yes, one other thing: please tell us where you got this question from.
Thanks
[ November 20, 2006: Message edited by: Barry Gaunt ]

[raja kanak]

At run time you will get the following exception
ArrayIndexOutOfBoundException

[RAMA KRISHNA AALLA]

I got 1 2 as output but expected Runtime exception.

The question was from K & B.

Thanks,

Rama Krishna

[Joe Harry]

Hi Guys,

What does the statement x = array.length return??? It returns 2 and that is why the o/p 1 2. Is it because array is a two dimensional array, array.length returns 2??

Can anyone explain on this??

[Joe Harry]

Ok, the array.length returns the no of rows. So that is why the O/P 1 2. I got it. It was worth discussing this topic here.

[RAMA KRISHNA AALLA]

What happens when the below statement executes

array[0]=args; (Command line Arguments : A 1 2 3)


Thanks,

Rama Krishna

[Joe Harry]

It gives 1 2 as the O/P

[Burkhard Hassel]

Hi ranchers,

tricky !

I added only one line to the output and invoked class A from another class:

import java.util.Arrays;
 
public class Main {
public static void main(String[] args) {
A.main(new String[] { "1", "2", "3" });
}
}
 
class A {
public static void main(String[] args) {
String[][] array = new String[2][2];
int x;
array[0] = args;
x = array.length;
for (int y = 0; y < x; y++) {
System.out.println(" " + array[0][y]);
}
System.out.println(Arrays.deepToString(array));
}
}

The last line (I don't mean the "}" ) prints
[[1, 2, 3], [null, null]]

Now what's the length of the array?
What's the length of array[0]?
What's the length of array[1]?


Yours,
Bu.

[Abdul Rehman]

Originally posted by RAMA KRISHNA CHOWDARY:
I got 1 2 as output but expected Runtime exception.

That's a common misconception in the mind of those who have worked in C++ or similar languages. In Java, there is no such thing as a two dimensional array; rather, nested arrays are arrays of arrays.
In your example, array contains two elements. These elements are actually references to arrays of String i.e. String[]. We can modify the reference contained in the first element of array, to point to any array of String, no matter what its size is.
Hope this will help you understand the output.

Thanks,
Abdul Rehman.

[RAMA KRISHNA AALLA]

Thanks Rehman for your explanation.

Regards,

Rama Krishna