Short-Circuit Problem

[Micheal John]

int z = 5;
if(++z > 5 || ++z > 6) z++; // z = 7 after this code

int z = 5;
if(++z > 5 | ++z > 6) z++; // z = 8 after this code
 
how z = 8 will be 8 in this case?

[Sanjeev Singh]

||(short circuit OR) don't bother to check the second OR if the first one is true while (|) bitwize OR does.

[annapurna madala]

As you said thats the short-circuit problem
In the first case, ++z>5 evaluates to true, so the ++z>6 will not be evaluated(because '||' is a short-circuit operator)
where as in the second case, even when the first operand evaluates to true ++z>6 will be executed giving the output as 8