method overloading and implicit casting

[Costa lamona]

Hi

public static synchronized void  main(String arg[]) throws Exception{   
  int i = 0;
  method(i);
 }
 static void method(long l) {
  System.out.println("long");
 }
 static void method(float i) {
  System.out.println("float");
 }
} 

//output is long

explain why? what are the rules when implicit casting is allowed for both methods
I thought , it will choose float because it is smaller in size!

Thanks

[Keith Lynn]

It is true that a long is stored in 64 bits and a float is stored in 32 bits, but that does not mean that a long is larger than a float. The whole numbers are stored exactly, but floating point numbers are stored differently.

A long is considered to be a subtype of float according to the Java Language Specification 4.10.1.

So the method that accepts a long is more specific than the method that accepts a float.

[Costa lamona]

Thanks Keith
This was very helpfull