wrapper and == question

[Mark Uppeteer]

Hi,

I don't understand why

System.out.println(new Boolean("true") == Boolean.parseBoolean("true"));

prints true.

and

System.out.println(new Boolean("true") == new Boolean("true"));

doesn't.
I thought when 'new' is involved you are actually bypassing the cache of the classes. Which seems to be so in the second example, but this doesn't seem to be the case in the first example (where there is a new involved))

Could someone explain this ?

thanks!

[Keith Lynn]

The reason is that the return type of Boolean.parseBoolean is a primitive boolean.

When == is applied to a boolean and a Boolean, then the Boolean is unboxed and == is boolean equality.

[Mark Uppeteer]

oops,that was actually something I should have been able to see myself..
I guess I was blinded by the 'new' and got confused.

Thanks a lot!


regards,
Mark