What is the output for First Snippet and Second Snippet?

[Mohammed Imran]

First Snippet:

class MyClass
{
public static void main(String []args)
{
final int i = 100;
byte b = i;
System.out.println(b);
}
}

Second Snippet:

class MyClass
{
public static void main(String []args)
{
int i = 100;
byte b = i;
System.out.println(b);
}
}

[Ulf Dittmer]

Welcome to JavaRanch.

That's quite easy to find out, isn't it?

[Neel Joshi]

The First Snippet will compile, run and print 100.
The second Snippet will not compile.

In the First Snippet, i is cmpile time constant and its value 100 is in the range of byte so no explicit casting is required.

In the Second Snippet, i is not compile time constant. So, you have to explicitly cast the value of integer i to byte.

byte b = (byte)i will work.
[ January 03, 2007: Message edited by: Neel Joshi ]

[Deepak Bala]

Is that a quiz or a question ?