Argument defined Annonymous Inner class

[Kasak Tahilramani]

 
public class Argumentannoys {
 
void method(){
Bar b =new Bar();
b.doStuff(new Foo(){//giving error at this line 1
public void foof(){System.out.println("foofy");
}
});
}
 

interface Foo{

public void foof();
}
public static void main(String[] args) {
Argumentannoys a=new Argumentannoys();
a.method();
 
}
 
}
class Bar{
void doStuff(){}
}
 

1:I am getting error at line 1 ,can someone explain Argument defined Annonymous Inner class with examples.K&B book Ch:8 inner Class.
2:Even my Class Bar is not implementing interface Foo ,how it is implementing the foof() method.

Confusion please explain!!!

[marc weber]

Your doStuff method in Bar is defined with no arguments, but you're trying to call it with a parameter.

[Kasak Tahilramani]

class Bar{

void doStuff(foo f){}
}

Even then it is giving error at the same line

[Anton Uwe]

You have to use the complete name of the Interface Foo, because it's an inner part of your class Argumentannoys. So you have to write

void doStuff(Argumentannoys.Foo x){}

or, so that you can see, that your anonymous implementer does his work,


void doStuff(Argumentannoys.Foo x){
x.foof();
}
[ January 14, 2007: Message edited by: Anton Uwe ]

[Kasak Tahilramani]

with which reference variable I can call my
public void foof(){System.out.println("foofy");
}

and get the output as foofy

[marc weber]

Originally posted by Kasak Tahilramani:
with which reference variable I can call my
public void foof...

I think Anton answered that question. Does this work for you?

[Barry Gaunt]

I thought this question was answered already in this topic.

[marc weber]

Kasak,

Once you've posted a question, please continue that discussion in the original thread instead of starting a duplicate thread on the same topic. When there are duplicates, people waste time by responding to questions that have already been answered.

Thanks.