Question on varargs

[victor kamat]

Consider the following code:

 
public class Test
{
static void prt(int... par)
{
for( int k=0; k<par.length; k++)
System.out.println(par[k]);
 
for(final int i : par)
System.out.println(i);
}
public  static void  main(String... args)
{ prt(1,2);}
}

This code compiles fine and puts out the expected output.
What has me confused is the "final" int the second for loop.
I would have thought that the code would not compile.
If we make k final in the 1st loop, code does not compile.
Can somebody explain this to me.
[ January 21, 2007: Message edited by: Barry Gaunt ]

[victor kamat]

I have answered my own question. In the loop body cannot change value of i

void prt(int... par)
{
for(final int i : par)
{
// in loop body cannot change i
}
}
[ January 21, 2007: Message edited by: Barry Gaunt ]