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super class

Arivu Selvi

Joined: Dec 06, 2006
Posts: 2
Can anybody explain how the output here is 22?

class Base {
int i;
Base() { add(1); }
void add(int v) { i += v; }
void print() { System.out.println(i); }

class Extension extends Base {
Extension() { add(2); }
void add(int v) { i += v*2; }

public class Qd073 {
public static void main(String[] args) {
bogo(new Extension());
static void bogo(Base b) {
Joe Harry
Ranch Hand

Joined: Sep 26, 2006
Posts: 10033

This question is explained in the Khalid Mughal's book itself.

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Vishal K Patel
Ranch Hand

Joined: Oct 20, 2006
Posts: 43
Here, when the is called, automatically super constructor will be called.

Form the super constructor, add method is called with argument 1. but the method from child class will be executed at run time as the original object is from child class.

This is the good example of polymorphisms.

I think it's enough to get the reason.....
I agree. Here's the link:
subject: super class
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