Call to function inside construction?

[raja kanak]

I got this question from www.jchq.net

 
public class BettyAck {
    public static void main(String argv[]){
BettyAck b =new BettyAck();
    }
    public BettyAck() {
Integer x = new Integer(10);
        findOut(x);
Integer y = new Integer(99);
        Integer z = y;
        z = null;
        findOut(y); 
        //here
    }
    public void  findOut(Integer y){
y = null;
        
    }
}

It compiles and run. I read that inside constructor, we can call only this and super then how come findOut(y) call works?

If my understanding is wrong, please correct. Thanks for any help.

rajakvk

[S Vilish]

I read that inside constructor, we can call only this and super

We can call any other method of the class inside the constructor.

Vilish

[Burkhard Hassel]

Hi raja,

it is true that in the first line of the constructor, we can only this or super.

Remember however, that if you don't put a call to this or super, the compiler provides an invisible call to super:

 
public class BettyAck {
public static void main(String argv[]) {
BettyAck b = new BettyAck();
}
 
public BettyAck() {
[B]super(); // invisible first line[/B]
Integer x = new Integer(10); // not really the first line
findOut(x);
Integer y = new Integer(99);
Integer z = y;
z = null;
findOut(y);
// here (something else unrelated to question)
}
 
public void findOut(Integer y) {
y = null;
}
}
 

Yours,
Bu.
[ February 17, 2007: Message edited by: Burkhard Hassel ]

[raja kanak]

thanks a lot for your efforts.