Exception logic doubt

[raja kanak]

public class q18 {
    static int call(int x) {
        try {
            System.out.println(x---x/0);
            return x--;
        } catch (Exception e) {
            System.out.println(--x-x%0);   //1
            return x--;
        } finally {
            return x--;
        }
    }
    public static void main(String... args) {
        System.out.println("value = " + call(5));
    }
}

In the above code I expect runtime exception but the code compiles and run giving output 3. What happens to the runtime error at //1
I can't understand the logic, can any one guide please!!

[Henry Wong]

In the above code I expect runtime exception but the code compiles and run giving output 3. What happens to the runtime error at //1

The runtime exception at "//1" got hidden/replaced by the value returned in the finally clause. This is why you should not throw exceptions or return values from the finally clause -- any exceptions thrown or value returned from the try/catch blocks will not complete.

Henry

[raja kanak]

I understand the above explantion like below
when an runtime exception occured inside a catch block and a finally clause is included then that exception is ignored/hidden. Am i right?

another doubt regarding the same code.
If any exception occured inside a catch block, still finally block run?

[Tommaso Nuccio]

Hi,

when a finally-block is declared, this finally-block is always called, whether there is an exception or not AND whether an exception is thrown.

A finally is not called, when the try/catch-part would shut down the virtual machine, using a System.exit(). But where would be the sense here?

Ciao,
Tommaso

[Shiva Mohan]

   
public class q18 {
static int call(int x) {
try {
System.out.println(x---x/0);
return x--;
} catch (Exception e) {
System.out.println(--x-x%0); 
return x--;
} finally {
return x--;
}
}
public static void main(String... args) {
System.out.println("value = " + call(5));
}
}
 

i got that runtimeException is hidden ,return statements of try and catch are hidden and finally gets executed.but i am confused how do we get the value 3.Please help me with which statements got executed.

[Anton Uwe]

Both System.out.println()-statements will each decrement x by 1, so the output is 3 (return x-- in finally block will return the actual value of x, which is 3).