array passing to method - doubt

[raja kanak]

    
class Comment {
    public static void main(String[] args) {
        int[] a;
        a = new int[0];
        call(a);
        System.out.println(a[0]);    //1
    }
    static void call(int[] a) {
        int[] b = {4,5,6};
        a = b;
        System.out.println(a[0]);
    }
}

The above code compiles fine but gives runtime exception ArrayIndexOutOfBoundsException at //1.

My doubt is
don't java pass reference to method argument?

[Henry Wong]

don't java pass reference to method argument?

Java pass a copy of the array reference. This means that if you change the elements of the array, it will change the original array. If you change the array reference itself, it will not affect the original reference.

Henry

[raja kanak]

    
public class TadKebab{
    public static void main(String argv[]){
new TadKebab();
    }
    private TadKebab(){
String[] Sa = {"Sam Smith", "John Smith"};
getName(Sa);
System.out.print(Sa[0]);
    }
 
    public void getName(String s[]){
s[0]="Coors";
    }
}
1 Compile time error, a constructor cannot be marked as private
2Compilation and output of "Sam Smith"
3 Compilation and output of "Coors"
4 Compilation, but runtime error.

The correct answer is 3. Now I got it. thanks a lot.