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Boxing Doubt

Sanjeev Narula
Greenhorn

Joined: Mar 16, 2007
Posts: 19
public class Boxing9 {
public static void main(String[] args) {
int i = 10;
method(i);
}
static void method(Object o){
System.out.println("Object called");
}
static void method(Number n){
System.out.println("Number called");
}
}


what will be answer, after boxing of primitive 'i' to Integer i. it should get widen. Since Integer is a Number and also Integer is a Object.

Which method will be called?
Wiyanto Ngasinur
Ranch Hand

Joined: Dec 11, 2006
Posts: 34
i think the method will be called is the most specific ones.
since i is primitive int, it will be boxing to Integer... then it will called method which parameter is Number, since is the more specific than Object.
sadasiva kumar
Ranch Hand

Joined: Oct 30, 2003
Posts: 91
Since Integer is a Number and also Integer is a Object.

Which method will be called?


Here you are passing Integer value 10 and you are not passing Object reference value.So automatically it calls the method which has Number as parameter.


SADASIVAKUMAR UTTI, SCJP1.4
A bend in the road is not the end of the road ... unless you fail to make the turn.
Scott Tiger
Greenhorn

Joined: Mar 23, 2007
Posts: 7
i also think it will invoke method(Number n) this method
 
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subject: Boxing Doubt