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Hanna Barenthin

Joined: Mar 13, 2007
Posts: 14
Hi again...

I have a question regarding Runtime-exceptions. Some seem to interrupt the running of the code (for example IllegalMonitorState Exception), i.e. the code beneath the place where the exception is thrown will not run.

However, when using parseInt() which throws a NumberFormatException, the code beneath still runs, like in ex 64:64 in the Master Exam.

How do I know when the program will stop and when it will continue?

BR, Hanna
Keith Lynn
Ranch Hand

Joined: Feb 07, 2005
Posts: 2398
When an exception occurs, the block it is in will terminate. So the code beneath it in the block will not run.
marc weber

Joined: Aug 31, 2004
Posts: 11343

Maybe it would help to post the code you're questioning, so we could walk you through it.

"We're kind of on the level of crossword puzzle writers... And no one ever goes to them and gives them an award." ~Joe Strummer
Hanna Barenthin

Joined: Mar 13, 2007
Posts: 14
Hi again!

When I was about to post my code I found the answer ;-) parseInt() will not throw an exception unless the string it receives is badly formatted and mine was not! Maybe a bit stupid but I first thought that it was always supposed to be thrown...

I agree. Here's the link:
subject: Exceptions
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