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Now my problem here is that LINE 1 can be written as c = c * a + b Here now "*" has a higher priority as "+" and the result must be c = (2 * 3) + 4 c = 10

Why is it 14?

Or does c *= a + b; c = c * a + c * b; c = c * (a + b); ?

Thanks in advance.

Ciao,<br /> Tommaso<br /> <br />~*~*~*~<br />There are 10 types of people, those who understand binary and those who don't.

the compund assignment operators have the lowest precedence of all the operators in javal allowin the expression on the right -hand side to be evaluated before the assignment so c * = a+b; will be x =((c)*(a+b))

This is from the Java Language Specification 15.26.2.

A compound assignment expression of the form E1 op = E2 is equivalent to E1 = (T )((E1) op (E2)), where T is the type of E1, except that E1 is evaluated only once.

Tommaso Nuccio
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Joined: Dec 11, 2006
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When I compiled I got 14, but I always thought it is the other way!!