Output needed

[Ankith suresh]

int b=9;
b = b +(b=3);
System.out.println(b);
Output??

[Barry Gaunt]

What do you get when you compile and run it?
What don't you understand about the answer you get? Please show some effort that you have tacked the problem.

[Ankith suresh]

Originally posted by Barry Gaunt:
What do you get when you compile and run it?
What don't you understand about the answer you get? Please show some effort that you have tacked the problem.

I excuted and got the output is 12.
But i want to know the flow of excution happening here

b=b+(b=3)

According to operator precedence (b=3) has to excute first rt?

so b= 3 + 3 right?

So answer is 6 ???

[Barry Gaunt]

No, take a look at how b = b + (b=3) is performed.
First the value of b(9) is pushed on the stack.
Then the value of evaluating b=3 (3) is pushed on the stack.

So the stack (from the top down) contains 3 and 9.
The result is the sum of those two stack entries (12), and that gets assigned to b.