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Output needed

Ankith suresh
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Joined: Jun 07, 2007
Posts: 42
int b=9;
b = b +(b=3);
System.out.println(b);
Output??
Barry Gaunt
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Joined: Aug 03, 2002
Posts: 7729
What do you get when you compile and run it?
What don't you understand about the answer you get? Please show some effort that you have tacked the problem.


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Ankith suresh
Ranch Hand

Joined: Jun 07, 2007
Posts: 42
Originally posted by Barry Gaunt:
What do you get when you compile and run it?
What don't you understand about the answer you get? Please show some effort that you have tacked the problem.


I excuted and got the output is 12.
But i want to know the flow of excution happening here

b=b+(b=3)

According to operator precedence (b=3) has to excute first rt?

so b= 3 + 3 right?

So answer is 6 ???
Barry Gaunt
Ranch Hand

Joined: Aug 03, 2002
Posts: 7729
No, take a look at how b = b + (b=3) is performed.
First the value of b(9) is pushed on the stack.
Then the value of evaluating b=3 (3) is pushed on the stack.

So the stack (from the top down) contains 3 and 9.
The result is the sum of those two stack entries (12), and that gets assigned to b.
 
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