doubt in continue and break

[Divya Gehlot]

  public class HarHam{
public static void main(String argv[]){
HarHam hh = new HarHam();
hh.go();
}
public void go(){
String har = new String ("har");
String ham = new String("har");
collar:
for(int i=0; i < 2 ; i ++){
if(har==ham){
  break collar;
}
if(i > 0){
continue collar;
}

System.out.print(i);
}
}
 
}  

1) Compile time error, System.out has no print method
2) No output at runtime
3) Output of 0
4) Compile error, break cannot occur after its target label

I expected the output to be 01 but when I run the above program got the ouput 0 . Can anybody explain me ?

[Nik Arora]

Hi divya,
When i is 0 it comes in the loop and checks for both the condition what you have written since both condition returns false it goes to next line and prints 0. Now i is 1 so the second condition satisfies that is if(i>0), in the if block you have written a continue statement now control goes back to the for loop. i value gets incremented now its value is 2 so the condition fails that is i<2 and control comes out of the for loop. So only 0 gets printed.

Regards
Nik

[nitin pokhriyal]

if(har==ham){ //never gets here because they are not equal


if(i > 0){
continue collar; }
System.out.print(i);

first time condition is false . so it will print 0. In second iteration i>0 condition will true and so it will go continue statement and loop will move to next iteration and then for loop condition will never be true for i after that so no SOP will be printed after first time

[Divya Gehlot]

thanks a alot. I got it

[Manfred Klug]

Hi,

somebody interested in a small variation of the program?

public class HarHam{
    public static void main(String argv[]){
        HarHam hh = new HarHam();
        hh.go();
    }
    public void go(){
        String har = "har";
        String ham = "har";
        collar:
        for(int i=0; i < 2 ; i ++){
            if(har==ham){
                break collar;
            }
            if(i > 0){
                continue collar;
            }
 
            System.out.print(i);
        }
    }
 
}

1) Compile time error, System.out has no print method
2) No output at runtime
3) Output of 0
4) Compile error, break cannot occur after its target label

[Ketul Shah]

code:

public class HarHam{
public static void main(String argv[]){
HarHam hh = new HarHam();
hh.go();
}
public void go(){
String har = "har";
String ham = "har";
collar:
for(int i=0; i < 2 ; i ++){
if(har==ham){
break collar;
}
if(i > 0){
continue collar;
}

System.out.print(i);
}
}

}

--------------------------------------
The answer for this is "No Output at runtime".

[suresh koutam]

yep
no output at runtime...
the first condition is met and the break takes it out of the for loop..


Suresh Koutam