Increment Operator

[Karthick Thiagarajan]

hi guys can any one clear my doubt?

public class Test
{
public static void main(String[] args) {
int i= 1;
i=i++;
i=i++;
i=i++;
i++;
System.out.println("the value of i=" +i);

}

Answer is 2


why the incremented values are not assigning to 'i'?

thanks in advance..

[alok Jain]

Hi ,
suppose you have a expression like
int x= 1 , y = 2 , z = 0;
z = x++ + ++y ;

now what happens is :
1) first the expression on the right hand side is evaluated as below :
a) first all the prefix operators are applied to the operands .
here in the above example since y has prefix operator y becomes 3 .

2) Now the expression is evaluated and the result of the expression is kept in a temporary location.
3) If the operands have any postfix operator that is evaluated for that operand .

4) Now the assignment to the LEFT HAND SIDE takes place . The LEFT HAND SIDE is given the value evaluated in the step 2 mentioned above .

..If you apply above rules correctly you should be able to get that the value of i as 2 .
let us see what happens for
int i = 1;
i= i++;

if you follow my rules above then
Step 1) Not applicable
Step 2) the value of the expression is 1.
Step 3) the value of i becomes 2
Step 4) the value of the expression evaluated to 1 is now assigned to i ( overwriting the value 2 )

[Abdullah Mamun]

You might want to read this excellent article regarding this topic.

[Jesper de Jong]

Karthick and Aalok,

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Please take a moment to carefully read the policy, and then change your name so that it is according to the policy. You can change your name by editing your profile.

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Jesper Young - Bartender

[fred rosenberger]

This question is asked quite often. In fact, we have a FAQ on it.

[raghu nagabandi]

I think the output is : 5

please chech in the system once.

[Karthick Thiagarajan]

Thank you guys

[Jesper de Jong]

Karthick T, please check your private messages.