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Strange question

 
Gitesh Ramchandani
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For the following code sample:

interface foo {
int k = 0;
}

public class test implements foo {
public static void main(String args[]) {
int i;
test t = new test();
i= t.k;
i= test.k;
i= foo.k;
}
}

What is the result?

A. Compilation succeeds.
B. An error at line 2 causes compilation to fail.
C. An error at line 9 causes compilation to fail.
D. An error at line 10 causes compilation to fail.
E. An error at line 11 causes compilation to fail.
Ans: A

Doubt: if I modify the code as
int i;
System.out.println(i);

test t = new test();
System.out.println(i);
i= t.k;

it gives compilation error �variable i might not have been initialized�.

Why is this so?

pls help
regards,
gitesh
 
Abdullah Mamun
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Eclipse IDE Mac
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int i;
System.out.println(i);
...
it gives compilation error �variable i might not have been initialized�.

Why is this so?


You cannot use any local variable before initializing. But you can use instance variables without initializing because they are initialized by the default values.
 
Jesper de Jong
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raghu nagabandi
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Interface variables are implecitly
public static final
 
Gitesh Ramchandani
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thanks for help.

The source of question is unknown, i found it in some materials (txt file) i downloaded from net.
 
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