This week's book giveaway is in the OCPJP forum. We're giving away four copies of OCA/OCP Java SE 7 Programmer I & II Study Guide and have Kathy Sierra & Bert Bates on-line! See this thread for details.

Hi all, I'm a new kid on the block. I've actually borrowed the study guide from kathy sierra for SCJP 1.4 (i couldn't get 1.5, i couldnt hunt down the book in the country i'm living in), so that was how I knew abt this webbie.

Question 1 Question on Shift Operators.

Taken from kathy's book :

x gets a hexadecimal value in it.. so it looks like this

but it states : When the leftmost bit is 1, the number is negative; and when it is 0, the number is positive.

Is it referring to the "1" from the hexadecimal "8"? It does not make sense, I thought the "1" was supposed to be part of the value. x holds a value of "-2147483648". What if i want a positive value of "2147483648"? I would have to change the first digit to 0. That'd make 32 bits of zeroes and the value would be 0 and not 2147483648 when printed out.

Question 2 Question on Bitwise Complement operator.

Taken from kathy's book :

Result:

In bit representation, the conversion looks like this, 0000 0000 0000 0000 0000 0000 0000 0101 // this is binary for 5 so when i use the ~ operator, it becomes : 1111 1111 1111 1111 1111 1111 1111 1010 // is this -6 in binary ?

Hope i can get some feedback. I'm stuck with these mis-conceptions, without clarifying, i cannot move on to understand further.

Originally posted by Clemi Clemi: Hi all, I'm a new kid on the block. I've actually borrowed the study guide from kathy sierra for SCJP 1.4 (i couldn't get 1.5, i couldnt hunt down the book in the country i'm living in), so that was how I knew abt this webbie.

Question 1 Question on Shift Operators.

Taken from kathy's book :

x gets a hexadecimal value in it.. so it looks like this

but it states : When the leftmost bit is 1, the number is negative; and when it is 0, the number is positive.

Is it referring to the "1" from the hexadecimal "8"? It does not make sense, I thought the "1" was supposed to be part of the value. x holds a value of "-2147483648". What if i want a positive value of "2147483648"? I would have to change the first digit to 0. That'd make 32 bits of zeroes and the value would be 0 and not 2147483648 when printed out.

In the original number, the 1 in the left-most position does make it a negative number. But when you shift the bits left by 1, that bit falls off and makes the number non-negative.

Question 2 Question on Bitwise Complement operator.

Taken from kathy's book :

Result:

In bit representation, the conversion looks like this, 0000 0000 0000 0000 0000 0000 0000 0101 // this is binary for 5 so when i use the ~ operator, it becomes : 1111 1111 1111 1111 1111 1111 1111 1010 // is this -6 in binary ?

Hope i can get some feedback. I'm stuck with these mis-conceptions, without clarifying, i cannot move on to understand further.

Thank you!

When you have a number with a 1 in the left-most bit position, the number is negative.

To figure out what the number is, flip all of the bits and add 1 to it.

If you flip the bits back, you get the bit representation of 5. When you add 1, you get 6.

So the number is -6. [ September 02, 2007: Message edited by: Keith Lynn ]

1111 1111 1111 1111 1111 1111 1111 0000 // i'll do this

1) If the left most bit is "1", meaning it's a negative, i'll have to flip all the bits 2) After flipping, i get 0000 0000 0000 0000 0000 0000 0000 1111 3) Which represents 1 + 2 + 4 + 8 = 15 4) Thereafter, I shall add 1 to it, resulting in 16 5) Then making it a negative number, -16 (correct answer?)

Another qn : If the left most bit is "0", meaning it's a Positive, i DO NOT have to flip all the bits, is that correct?

Thanks for your first contribution to this forum and...

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