Override method

[rex tony]

[code]
class Super {
public float getNum() { return 3.0f; }
}

public class Sub extends Super {
A. public void getNum() { }
B. public void getNum(double d) { }
C. public float getNum() { return 4.0f; }
D. public double getNum(float d) { return 4.0d; }
}
[\code]
At the Compile time Exception at A.How?
[ October 24, 2007: Message edited by: rex tony ]

[Tarun Chauhan]

Rex Tony-
I think the problem is that you are trying to overload a method with same arguments which is not legal. I tried to compile the code and following is the result.

    
Sub.java:7: getNum(double) is already defined in Sub
 public void getNum(double d) { }
             ^
1 error
 

[Raphael Kou]

Yes, Answer A tries to override the method and one of the rules says that the return typ must be the same (in this case float) or a subtyp.

[rex tony]

Hello Dzu-I Kou
Return type void is sub Type of Float?.If so,Tell me the Hierachy for the return type.

[Raphael Kou]

No, "void" is "void" and not a class so it can't be a subclass of any class.
So A won't compile!!

One of the rules says that when you override the return typ must be the same or a subtype.

So lets assume you have this class with the getNum() Method but instead of float the return type is "Number"

class Super {
public Number getNum() { return 3.0f; }
}

Now when you override the getNum() method you must write the same typ

public Number getNum() { return 3.0f; }

or a subtyp of "Number" like Integer

public Integer getNum() { return 3.0f; }
[ October 24, 2007: Message edited by: Dzu-I Kou ]