Can anybody explain the reason for the following out put ?
Kelvin Chenhao Lim
posted 8 years ago
The Byte.toString() method returns a new String instance each time you call it. As a result, the expression "(b1.toString() == b1.toString())" actually creates two objects and compares their references, which will of course not be equal. However, "b1.toString().equals(b1.toString())" will evaluate to true, since both String objects contain the text "12". [ October 29, 2007: Message edited by: Kelvin Lim ]