Doubt about a float value

[Justen Hill]

int a = 8;
int b = 3;
float c = a++/b--;
System.out.println(c);

Why does this produce 2.0? Shouldn't the result be able to handle a more accurate answer?

[Bear Bibeault]

Think about at what point in the calculatiuon of your expression the implicit conversion from int to float occurs.

[fred rosenberger]

I would say that that is pretty darn accurate. In fact, I would say it is precise.

what would you get if you did this?

int a = 8;
int b = 3;
int c = a++/b--;
float d = c;
System.out.println(d);

[Justen Hill]

I see it now. The division of the ints occurs first, then the result is stuffed in a float.

Is it actually a float since it doesn't have an 'f' assignment or is it a double?