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enum doubt

zartab ameen

Joined: May 01, 2007
Posts: 13
Hi this is one of the question i found in mock exam

class Stepper{
enum Roman {I,V,X,L,C,M}
public static void main(String... bang){
int x=7;
int z=2;

Roman r=Roman.X;
case C:r=Roman.L;break;
case X:r=Roman.C;
case L:if(r.ordinal()>2)z+=5;
case M:x++;
i have just one statement which i did not understand

case L:if(r.ordinal()>2)z+=5;
please can you explain me what does above statement mean,i really don't
understand what ordinal is.

Julio Eneriz

Joined: Nov 28, 2007
Posts: 15
From the Api (http://java.sun.com/j2se/1.5.0/docs/api/) Enum page

Returns the ordinal of this enumeration constant (its position in its enum declaration, where the initial constant is assigned an ordinal of zero).

So the behaviour depends on the ordinal I = 0, V = 1, X = 2 and so on, so L,C and M > 2.

What I'm not sure is the purpose of the code.
I agree. Here's the link: http://aspose.com/file-tools
subject: enum doubt
jQuery in Action, 3rd edition