New question on K&B Chapter 9 Question 17

[Karen Marie]

public class TwoThreads{
static Thread laurel,hardy;
public static void main(String[] args){
laurel=new Thread(){
public void run() {
System.out.println("A");
try{
hardy.sleep(1000);
} catch(Exception e){
System.out.println("B");
}
System.out.println("C");
}
};
hardy=new Thread() {
public void run(){
System.out.println("D");
try{
laurel.wait();
}catch(Exception e){
System.out.println("E");
}
System.out.println("F");
}
};
laurel.start();
hardy.start();
}
}

Why does F execute? I would have thought after the exception was thrown it would stop execution.

[kurt hanni]

the exception in hardy thread was handled by the catch block, so code will continue on and "F" will be printed.