but if i make final byte b=1; then it works reason?
posted 8 years ago
The reason it cannot covert it without it being final is because your byte variable could be negative, which is out of bounds for a char. By making it final you are stating that "a" 100% for sure will be positive.
If you change it to
final byte b = -104; char c = 2; c = b;
It will still throw the error because it needs to know you are giving it a positive number. [ December 10, 2007: Message edited by: Panseer Kaur ]