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Doubt in implict conversion

sakthi moorthy
Ranch Hand

Joined: Oct 17, 2007
Posts: 54
byte b = 1;
char c = 2;
c = b;//not allowed

but if i make
final byte b=1;
then it works reason?
Panseer Kaur
Ranch Hand

Joined: Nov 01, 2007
Posts: 44
The reason it cannot covert it without it being final is because your byte variable could be negative, which is out of bounds for a char. By making it final you are stating that "a" 100% for sure will be positive.

If you change it to

final byte b = -104;
char c = 2;
c = b;

It will still throw the error because it needs to know you are giving it a positive number.
[ December 10, 2007: Message edited by: Panseer Kaur ]
I agree. Here's the link:
subject: Doubt in implict conversion
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