Can someone help me with this

[Neeta Avasthi]

Hello,
I am new to the group of ranchers...just wanted to clarify a doubt:

This code is there in the K & B book...chapter 3. The output for the program is :

same object
meaningfully equal
different objects
meaningfully equal

I am really confused as to how both Line A and B can be executed.

class Test
{
public static void main(String agrs[])
{
Integer i3 = 100;
Integer i4 = 100;
if(i3 == i4) System.out.println("same object");//line A
if(i3.equals(i4)) System.out.println("meaningfully equal");

Integer i1 = 1000;
Integer i2 = 1000;
if(i1 != i2) System.out.println("different objects");//line B
if(i1.equals(i2)) System.out.println("meaningfully equal");
}
}

Thanks in Advance.

[Krishna Srinivasan]

Normally, when the primitive types are boxed into the wrapper types, the JVM allocates memory and creates a new object. But for some special cases, the JVM reuses the same object.

The following is the list of primitives stored as immutable objects:

boolean values true and false
All byte values
short values between -128 and 127
int values between -128 and 127
char in the range \u0000 to \u007F

read this article for detailed explanation.
[ January 09, 2008: Message edited by: Krishna Srinivasan ]

[Dean Jones]

Integer i=10;Integer j=new Integer(10);System.out.println(i==j);

prints false

Integer i1=10;Integer j1=10;System.out.println(i1==j1);

prints true;

Integer i2=new Integer(10);Integer j2=new Integer(10);System.out.println(i2==j2);

prints false