enthuware error?

[Vishwanath Krishnamurthi]

Hi,

Q.No 23 of Test6 in enthuware, (its a DnD so, I couldn't copy and paste it here..)

gives an explanation like this regarding the natural ordering for strings:

3. Collections.sort(collection) method sorts the elements of the given collection in the natural order of it elements. Natural order means: as governed by the compareTo() method of the elements. I case of String elements, the natural order is: space < lower case < upper case. Here, the output is expected to be in reverse order, therefore, we need a reverse order Comparator. Collections.reverseOrder() returns such a comparator.

and the answer for the question too was based on this..

But isn't it:
space < upper case < lower case ?

Thanks,
Vishwa.
[ January 20, 2008: Message edited by: Vishwanath Murthi ]

[Burkhard Hassel]

Howdy Vishwa,

you are right.

public static void main(String[] args) {
List list = new Vector();
list.add(" ");
list.add("a");
list.add("A");
Collections.sort(list);
System.out.println(list);
}

prints
[ , A, a]


Yours,
Bu.

[Burkhard Hassel]

...
But you are not right in calling it "errata".
Know why?

[Vishwanath Krishnamurthi]

Oh! Its an "error"

[Paul Anilprem]

Hi Vishwanath,
Thanks for pointing it out. The order is indeed space < upper case < lower case, but the given answer is correct and will remain same (in this particular situation).

[Vishwanath Krishnamurthi]

Hi Paul,

The question says,

Complete the Code so that it will print [amy, Adam, audrey] when run.

and (the completed code, the answer given)...

import java.util.*;
public class TestClass
   {
       public static List<String> getNameList()
              {
                 String[] sa={"amy","audrey","Adam"};
                 List<String> list=Arrays.asList(sa);
                 return list;
               }
 
        public static void main(String[] args)
              {
                 List<String> list=getNameList();
                 Comparator c=Collections.reverseOrder();
                 Collections.sort(list,c);
                  System.out.println(list);
                }
    }
    

gives an O/P: [audrey, amy, Adam] (as expected) and not [amy, Adam, audrey]...
[ January 20, 2008: Message edited by: Vishwanath Murthi ]

[Paul Anilprem]

Vishwanath,
That's because you aren't using the same code as given in the question. What you have written is

String[] sa={"amy","audrey","Adam"};

but the code in question is

String[] sa={"amy"," audrey","Adam"};

HTH,
Paul.

[Vishwanath Krishnamurthi]

Thanks..