How many String are created??

[Sabrina Biccari]

Hi, I'm sabrina ..I have doubts about: How many String this code creates and where (pool Memory or no pool Memory)

String s = new String("Java");
StringBuffer sb = new StringBuffer();
sb.append(s + " " + "is" + " " + "cool");

[Nadeem Khan]

Hi, here what i "think":

String s = new String("Java");
------If this means the same as following:
String s = new String();//A String got created in non-pool memory!
s = "java"; // A string "java" created in pool memory!

StringBuffer sb = new StringBuffer();
// No string created!

sb.append(s + " " + "is" + " " + "cool");
// "is" in pool
//"cool" in pool
//" " in pool
//"java is cool" in pool //and that rhymes

[Sabrina Biccari]

Thanks Nadeem,
so I have six String created and the StringBuffer is not created.!!!

[Sabrina Biccari]

Sorry,
so I have six String created and an StringBuffer.

If I have another code:

StringBuffer sb = new StringBuffer("java");

I have only an StringBuffer created or I have an StringBuffer created and an String (java) created in poolMemoory??

[Jart Bo]

Hi Sabrina,
My guess is that there would be 7 String objects here.

   
String s = new String("Java");   // 2 String objects ( 1 on mem. pool)
StringBuffer sb = new StringBuffer();  // 1 StringBuffer object
sb.append(s + " " + "is" + " " + "cool");  // 5 String objects 
 

[ February 15, 2008: Message edited by: Jart Bo ]

[Ali Khalfan]

Hi Sabrina,
My guess is that there would be 7 String objects here.

you mean 8.

2 in the first statement, 1 in the second, and 5 in the third

2+1+5 = 8

[Jart Bo]

Hi Ali,

I was thinking the 2nd line creates a StringBuffer object, not a String. Please correct me if I'm wrong. Thanks!

[Dean Jones]

Somebody please clarify

[Alex Belisle Turcot]

Originally posted by Sabrina Biccari:

String s = new String("Java"); //2
StringBuffer sb = new StringBuffer(); //0
sb.append(s + " " + "is" + " " + "cool"); //5

I would say 7 String objects created.

If you wanna be tricky, the part I'm not sure is how the strings on the 3rd line are concatenated:


" " //1
"is" //2
" " //3
"cool" //4
"Java is cool" //5

OR

" " //1
"is" //2
" " //3
"cool" //4
"java " //5
"java is" //6
"java is " //7
"Java is cool" //8

Alex
[ February 18, 2008: Message edited by: Alex Belisle Turcot ]

[Abhijit Das]

  
   String s = new String("JAVA");

All are saying that the above line creates two objects. One object is "JAVA" referred by 's' and what is the other object and reference variable to refer it.
thanks

[Nadeem Khan]

String s = new String("JAVA");

What i inferred from K & B, it creates two objects - "java" in pool memory and another object (new String()) in non-pool.And s points to "java".

Can someone please explain the relation between these two objects getting created here?