To find the Medium

[John Wenn]

import java.util.*;
 
class Worm{
     public static void main(String[] args) {
        System.out.println("Enter your text here:");
        Scanner a = new Scanner(System.in);
        String s = a.nextLine();
        String [] s1 = s.split(" ");
        int len = s1.length;
        int sum = 0;
        for (int i = 0; i<len; i++){
            sum += Integer.parseInt(s1[i]);
        }
        System.out.println("Sum:"+ sum);
        System.out.println("Average:"+ sum/2);
       
        }
    }

Can anyone find the medium of a given input? Using this code I have tried but I failed
But I think there�s a easy way of doing that,
Medium means
Input : 2 4 5 6 6 6 7 7 8
Considering on above number sequence the medium is 6
Please someone can figure this out leave a comment



[BPSouther: Added code tags]
[ March 10, 2008: Message edited by: Ben Souther ]

[Ben Souther]

When you say it failed, what do you mean exactly?
What results were you expecting?
What results did you see?

[marc weber]

I think it's the "median" you're after.

Before trying to code this, can you describe the steps you need to take (considering that the input might not always be ordered)?

Also, your calculation for "average" (mean) will only work if you have 2 elements (or if all your elements are zero). Do you see why?

[Rohit Garg]

The formula you are using to find out average is incorrect. It is not always 'sum/2'. The correct formula is 'sum/number of terms' instead.

Hope this helps!

[Hamsagayathri Palanisamy]

Hi,
To find the median of the series,the following code can be used.

import java.util.*;
 
class Worm{
 
public static void main(String[] args) {
 
System.out.println("Enter your text here:");
 
int count=0;
int median = 0;
Scanner a = new Scanner(System.in);
String s = a.nextLine();
String [] s1 = s.split(" ");
int len = s1.length;
int sum = 0;
for (int i = 0; i<len; i++){
sum += Integer.parseInt(s1[i]);
count +=1;
}
System.out.println("Sum:"+ sum);
System.out.println("Average:"+ sum/2);
if((count % 2)==0){
median =Integer.parseInt(s1[(count/2)-1])+Integer.parseInt(s1[count/2]);
 
}
else
median=Integer.parseInt(s1[(count-1)/2]);
 

System.out.println("Median is ::::::::::"+median);
 

}    }
 

Hope this helps you.
-Thanks & Regards,
Hamsa

[Hamsagayathri Palanisamy]

Hi,
To find the median of the series,the following code can be used.

import java.util.*;
 
class Worm{
 
public static void main(String[] args) {
 
System.out.println("Enter your text here:");
 
int count=0;
int median = 0;
Scanner a = new Scanner(System.in);
String s = a.nextLine();
String [] s1 = s.split(" ");
int len = s1.length;
int sum = 0;
for (int i = 0; i<len; i++){
sum += Integer.parseInt(s1[i]);
count +=1;
}
System.out.println("Sum:"+ sum);
System.out.println("Average:"+ sum/2);
if((count % 2)==0){
median =Integer.parseInt(s1[(count/2)-1])+Integer.parseInt(s1[count/2]);
 
}
else
median=Integer.parseInt(s1[(count-1)/2]);
 

System.out.println("Median is ::::::::::"+median);
 

}    }
 

Hope this helps you.
-Thanks & Regards,
Hamsa

[agilemanoj kumar]

import java.util.*;
 
class Worm{
 
public static void main(String[] args) {
 
System.out.println("Enter your text here:");
 
int count=0;
int median = 0;
int median_even1 = 0;
int median_even2 = 0;
Scanner a = new Scanner(System.in);
String s = a.nextLine();
String [] s1 = s.split(" ");
int len = s1.length;
int sum = 0;
for (int i = 0; i<len; i++){
sum += Integer.parseInt(s1[i]);
count +=1;
}
System.out.println("Sum:"+ sum);
System.out.println("Average:"+ sum/2);
if((count % 2)==0){
median_even1 =Integer.parseInt(s1[(count/2)-1]);
median_even2 =Integer.parseInt(s1[count/2]);
 
}
else
median=Integer.parseInt(s1[(count-1)/2]);
 
 
System.out.println("Median is ::::::::::"+median);
 
 
}    }

If number of integers entered is an even number, then there will be two medians.
If no. of integers entered is an odd number, then only one median we will have...
[ March 18, 2008: Message edited by: agilemanoj kumar ]

[Bert Bates]

and this applies to the SCJP how?

[Hamsagayathri Palanisamy]

Originally posted by agilemanoj kumar:

If number of integers entered is an even number, then there will be two medians.
If no. of integers entered is an odd number, then only one median we will have...

[ March 18, 2008: Message edited by: agilemanoj kumar ]

Hi agilemanoj,
if the number of integers entered is even number,i think there is no two medians, For example:
Integers entered are:
1 2 3 4 5 6
Then Median is: (3+4) /2 = 3.5
and if the integers entered are: 1 2 3 4 5
Median is: 3
I hope above one is median calculation and please correct me if i'm wrong.

-Thanks & Regards,
Hamsa