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Consider this code.

Sanket Modi
Ranch Hand

Joined: Mar 10, 2008
Posts: 30
Consider this code.
public class Test {
public static void main(String[] args){
for(int j = 0; j < 1 ; j++)
if (j < 1) continue innerLoop;
innerLoop: for(int i = 0; i < 2; i++)
System.out.println("Hello world");
What is the result of attempting to compile and run this.

Thanks and regards,<br />SanKet Modi
marc weber

Joined: Aug 31, 2004
Posts: 11343

Originally posted by Sanket Modi:
... What is the result of attempting to compile and run this.

Fortunately, Sun provides free tools (javac and java) for testing this.

Do you have a Java JDK installed on your machine?

"We're kind of on the level of crossword puzzle writers... And no one ever goes to them and gives them an award." ~Joe Strummer
Gaurav Joshi

Joined: Mar 08, 2008
Posts: 18
Hi Sanket Modi,

The above code will not complie as Label are like identifiers and the statement using these label(break or continue) must be in the scope of the label
I agree. Here's the link:
subject: Consider this code.
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