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round method

 
sarathy rambha
Greenhorn
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Hi,
I see compilation while compiling below program. But since round(float) returns int, I am not sure why it thinks return type is double.

float ddd = 3.5;
int j = Math.round(ddd);


Math1.java:84: possible loss of precision
found : double
required: float
float ddd = 3.5;
 
Ulf Dittmer
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The message is talking about the first line of code, not the second. "3.5" is a double, and it gets assigned to a float.
 
Deepak Bala
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The Math class is not part of the exam by the way. As for the error Ulf is right, its on the first line
 
Jesper de Jong
Java Cowboy
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For float literals, you need to append a letter f to the number, like this:

float ddd = 3.5f;
 
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