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|| and |

 
sumaraghavi ragha
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Posts: 118
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Hi All,
see the following code and expalin me the difference etween "||" and "|"

i am not a bigneer but getting confussion.


int z = 5;
if(++z > 5 || ++z > 6) z++; // z = 7 after this code
versus:
int z = 5;
if(++z > 5 | ++z > 6) z++; // z = 8 after this code
 
Saurabh V Vakil
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Posts: 14
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Originally posted by sumaraghavi ragha:



int z = 5;
if(++z > 5 || ++z > 6) z++; // z = 7 after this code
versus:
int z = 5;
if(++z > 5 | ++z > 6) z++; // z = 8 after this code



if(++z > 5 || ++z > 6) z++;
uses short-circuit OR(||). short-circuit OR returns true if either operand is true. since z becomes 6 after entering if, the first condition evaluates to true. since the first operand returns true, it never bothers to check the second condition. so the if() is exited after checking ++z > 6 after which z is incremented(z++). hence the value is 7.

but the second case- if(++z > 5 | ++z > 6) z++;
uses non short-circuit OR, which, always evaluates both sides of the expression. when first operand is evaluated, z becomes 6. when second operand is evaluated, z becomes 7. finally, z is again incremented to become 8.
the important thing to remember is this: while using short-circuit or(||), if the first operand in the expression evaluates to true, the second operand will never be evaluated. but when you use non short-circuit or(|), second operand will be evaluated regardless of whether the first operand returns true or false. hope this helps.
 
Deepak Bala
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Originally posted by sumaraghavi ragha:
Hi All,
see the following code and expalin me the difference etween "||" and "|"

i am not a bigneer but getting confussion.


int z = 5;
if(++z > 5 || ++z > 6) z++; // z = 7 after this code
versus:
int z = 5;
if(++z > 5 | ++z > 6) z++; // z = 8 after this code


Have a look at short circuit operators. The way an expression is evaluated changes based on whether the operator is shorted or not
 
sumaraghavi ragha
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Posts: 118
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Thanks lot
 
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