The code is giving Compiler Error because the method say() in Super is available to SubTwo & SubOne via inheritance though its access is protected. So you do not need any reference to access them, they can be access just be their name.
SCJP 1.4 - 88%<br />SCWCD 1.5 - Preparing
Joined: Apr 15, 2008
Originally posted by Harshit Rastogi: Hi The line 7 and 8 gives error because you can acces a protected method only via class which has inherited it and not by directly creating a object of a class in a different package.
Let me rephrase it The line 7 and 8 gives error because you can acces a protected method only via class object (SubTwo) which has inherited it and not by directly creating a object of a class directly (Super, SubOne)in a different package.
Joined: Nov 05, 2007
I have slightly modified the code.
Thanks. I kind of rememeber something about accesing protected members through inheritance and not by reference... But i still can't the right statement for acessing say() in Super and SubOne class.
If i could get some help with that.... [ September 11, 2008: Message edited by: Nabila Mohammad ]
Joined: Aug 28, 2008
For the code you provided at the start, you can access the say() of Super by say("Java")...
[ September 12, 2008: Message edited by: Paul Somnath ]
Hi Paul, Thanks for the explanation. I had already gone through the website as well as the K&B.
However they have both mentioned accessing variable in the Parent class- which has not been re defined in the child class.
If i have defined a say() method in all the three classes - Super,Subone and SubTwo Or a variable s in all the three - that case how do I call the variable or method in Super or SubOne class because it will always give the value of SubTwo.I mean is it even possible!? [ September 12, 2008: Message edited by: Nabila Mohammad ]
I’ve looked at a lot of different solutions, and in my humble opinion Aspose is the way to go. Here’s the link: http://aspose.com