Can Any Explain This Code...

[Thangaraj Selvamani]

class SuperCafe4Java {
public Object get (Object o) {
return ("SuperCafe4Java");
}
}

class SubCafe4Java extends SuperCafe4Java {
public Object get (String o) {
return ("SubCafe4Java");
}
}

class TestCafe4Java {
public static void main (String[] arguments) {
SuperCafe4Java superFoo;
SubCafe4Java subFoo;

superFoo = new SubCafe4Java();
System.out.println (superFoo.get("super"));

subFoo = new SubCafe4Java();
superFoo = subFoo;
System.out.println (superFoo.get("super"));
}
}

OutPut:SuperCafe4Java
SuperCafe4Java

[Ankit Garg]

Well the output is

SuperCafe4Java
SuperCafe4Java

because get(Object o) is not overridden by get(String o). Instead the two methods are overloaded. So when you call get("super") with a SuperCafe4Java class reference, the compiler looks for a method matching get("super") in the SuperCafe4Java class. It finds the get(Object o) method matching this method (as get(String o) is not available in SuperCafe4Java). So that method is called.

[M Srilatha]

Here get() method of SuperCafe4Java is overloaded in the sub class SubCafe4Java.
Its not overridden.(Overridden method calls will be determined at run time)
And the calls to the overloaded methods will be determined at compile time.

superFoo.get("super")

So the get method in SuperCafe4Java will be executed not the one in SubCafe4Java.

See page 109 of K&B 5.0 for more info!

Hope this is clear!

[Thangaraj Selvamani]

But When Im Running This Two Code...Getting Different OutPut

    
class SuperCafe4Java {
public Object get (String o) {
return ("SuperCafe4Java");
}
}
 
class SubCafe4Java extends SuperCafe4Java {
public Object get (Object o){
return ("SubCafe4Java");
}
}
 
class TestCafe4Java {
public static void main (String[] arguments) {
SuperCafe4Java superFoo;
SubCafe4Java subFoo;
 
superFoo = new SubCafe4Java();
System.out.println (superFoo.get("super"));
 
//subFoo = new SubCafe4Java();
 subFoo = (SubCafe4Java)superFoo;
System.out.println (subFoo.get("super"));
}
}
 
output is : SuperCafe4Java
            SuperCafe4Java

class SuperCafe4Java {
public Object get (Object o) {
return ("SuperCafe4Java");
}
}
 
class SubCafe4Java extends SuperCafe4Java {
public Object get (String o){
return ("SubCafe4Java");
}
}
 
class TestCafe4Java {
public static void main (String[] arguments) {
SuperCafe4Java superFoo;
SubCafe4Java subFoo;
 
superFoo = new SubCafe4Java();
System.out.println (superFoo.get("super"));
 
//subFoo = new SubCafe4Java();
 subFoo = (SubCafe4Java)superFoo;
System.out.println (subFoo.get("super"));
}
}
 
output :SuperCafe4Java
        SubCafe4Java
         

[M Srilatha]

 SuperCafe4Java superFoo;
SubCafe4Java subFoo;
 
superFoo = new SubCafe4Java();
System.out.println (superFoo.get("super"));
                //[B]here get() method from SuperCafe4Java will get executed and the output is SuperCafe4Java[/B]

 subFoo = (SubCafe4Java)superFoo;
System.out.println (subFoo.get("super"));   
//[B]here there two are methods available one is get(Object o)which is //inherited from SuperCafe4Java and get(String s) which is defined in //SubCafe4Java. As we are passing a string object("super"),the method //get(String s)(as it is more specific) will be executed. So the output is //SubCafe4Java.[/B]

[Thangaraj Selvamani]

Thank you...My Doubt Has got cleared...