friends This is my first post in this category though i have been a regular in some other parts of the ranch I am facing a unique problem first of all i am using Tomcat with JSP. What i want to do is accept a folder name from the user and create a folder by that name. I have written a bean for this which goes.
my problem is that this code is working fine on my local machine but when i use it on the server it is creating a folder in some unknown place. Suppose i have a folder "A" inside which i am placing my class file. My questions: 1) Which of the methods will return me the String "root:\A\" because most of the methods are returning me "root:\A\directoryname" or "directoryname" where directoryname = the String that i am passing in the file object f (c the code)so that i can pass it in the first argument of f and make a directory in the current directory 2)How do i create a directory in any place i want. Eg suppose i have my class file placed in c:/tomcat/webapps/classes and i want to create the directory in c:/tomcat/webapps/application/upload Any ideas will be highly appritiated URGENT Amit [This message has been edited by Amit Roy (edited March 20, 2001).] [This message has been edited by Amit Roy (edited March 20, 2001).] [This message has been edited by Amit Roy (edited March 20, 2001).]
ServletContext.getRealPath("relativePath\fileName") will give us the real path of the file starting from root. If the server machine is windows, it will give out c:\tomcat\....\whateverdir\fileName regds maha anna
subject: What is the method to get the current directory(please read)