Hello everybody, I am trying to make simple upload file through html form I used Jakarta Commons FileUpload I have made the code typically like jakarta description : ====================upload.jsp========================= <%@ page import="org.apache.commons.fileupload.*,java.util.*,java.io.*" %> <% // Check that we have a file upload request boolean isMultipart = FileUpload.isMultipartContent(request);
// Create a new file upload handler DiskFileUpload upload = new DiskFileUpload();
// Parse the request List /* FileItem */ items = upload.parseRequest(request);
// Process the uploaded items Iterator iter = items.iterator();
while (iter.hasNext()) { FileItem item = (FileItem) iter.next();
if (item.isFormField()) { out.println("hi , this is form based item "+item.getFieldName()+" "+item.getString()+"<BR>"); } else { String fieldName = item.getFieldName(); String fileName = item.getName(); String contentType = item.getContentType(); boolean isInMemory = item.isInMemory(); long sizeInBytes = item.getSize();
InputStream uploadedStream = item.getInputStream(); uploadedStream.close(); out.println("hi , this is uploaded item "+item.getFieldName()+" "+item.getName()+" "+item.getName()+" "+item.getSize()+"<BR>"); }
also this is the form i am using : ==============form.html============= <form method="post" ACTION="upload.jsp" name="upform" ENCTYPE='multipart/form-data'> <input type="file" name="uploadfile"> <p> <input type="submit" name="Submit" value="Submit"> <input type="reset" name="Reset" value="Reset"> <input type="hidden" name="action" value="upload">
</form> ====================================
the upload.jsp works fine without errors , and generate some infromation about the file i want to upload , its name , its size ... but i don't know where this file is uploaded ???
i searched on the server just beside the upload.jsp page , but i didn't find any uploaded file !
can any one help me and tell me what i am missing in this code ? or, if the file is really uploaded , where is it , and how i can define a specific place to upload it ?
thank you very much in advance
Hesham Katon<br />SCJP 1.2<br />SCWCD 1.4<br />Better to light a candle than to curse the darkness
With these lines you are not reading the inputstream. Create a file object with this input stream and write it out to a place on disk the server has access to. The way it is now the file attributes are only pulled from the request and never written to disk.
Jeremy Wilson
hesham katon
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Joined: Dec 18, 2002
Posts: 82
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thanks Jeremy , but can you help me with some code example .. this is what i have tried to do , but still not workin
// then i must convert the file into bytes to write it byte[] byteArray=new byte[uploadedFile.available()];
uploadedFile.read(byteArray); FileOutputStream os = new FileOutputStream(serverFile); os.write(byteArray); os.close(); ============================================================= the code is work without exception but still no result on the disk wish you can help