This week's book giveaway is in the OO, Patterns, UML and Refactoring forum. We're giving away four copies of Refactoring for Software Design Smells: Managing Technical Debt and have Girish Suryanarayana, Ganesh Samarthyam & Tushar Sharma on-line! See this thread for details.
I'm new here. I need your help with the browser back button. The sequence of the jsp pages are: page 1 -> page 2 -> page 3. On page 2, there is an 'Export to Excel' button. When user clicks on it, it goes back to the servlet and generate an Excel file and downloads it to jsp page 3. Then when user clicks on the Browser back button on page 3, it does not go back to page 2, it goes back to page 1 instead. How can I control the 'backto' page on jsp page 3, which is the excel file page? It is obviously treated as page 2.
a quick hack would be to use response.sendRedirect in ur servlet to get to the JSP page so that page 3 is treated as it should be... I am assuming that the servlet forwards the request to page 3 using requestdispatcher...
We're pleased to have you here with us on the Ranch, but there are a few rules that need to be followed, and one is that proper names are required. Please take a look at the JavaRanch Naming Policy and adjust your display name to match it.
In particular, your display name must be a first and a last name separated by a space character, and must not be obviously fictitious.
Thanks for your reply. I did try to use redirect and it didn't work. The erro message I got is:
Exception happened: com.ibm.servlet.engine.webapp.WebAppErrorReport: Please call the System Administrator.
The reason is that, we are using STRUTS framework. Every action has to return ActionForward from the executeBody() method. In order to use the redirect, I had to return null for that method and it caused this error.
Any solutions for that?
I’ve looked at a lot of different solutions, and in my humble opinion Aspose is the way to go. Here’s the link: http://aspose.com