Upload and Download files just like attachments in JSP

Hi everyone,
I am using JSP as a front-end view purpose,
From this page I have to push the data to one of the Action Request System form (AR System 6.3). I am using ARS JAVA API.
As per requirement I have to upload one file from user on JSP and have to push it to this back-end form.
I tried JavaZoom�s javazoom.upload class but its giving me a error and I couldn�t fine this class file anywhere. So this code didn�t work finally.
I need a urgent solution friends.
Please respond with some positive solutions.
Thank you,
Kaushal.

We have a file upload entry in our faq.
See:
http://faq.javaranch.com/search?FileUpload

Hai Ben,
i am using common file upload by jakarta to yupload file from client side to server i am having error while doing so....Can anyone solve the problem
Error :
org.apache.jasper.JasperException: Unable to compile class for JSP

An error occurred at line: 7 in the jsp file: /ProcessFileUpload.jsp
Generated servlet error:
ServletFileUpload cannot be resolved to a type

An error occurred at line: 7 in the jsp file: /ProcessFileUpload.jsp
Generated servlet error:
ServletFileUpload cannot be resolved to a type

An error occurred at line: 7 in the jsp file: /ProcessFileUpload.jsp
Generated servlet error:
FileItemIterator cannot be resolved to a type

An error occurred at line: 7 in the jsp file: /ProcessFileUpload.jsp
Generated servlet error:
FileItemStream cannot be resolved to a type

An error occurred at line: 7 in the jsp file: /ProcessFileUpload.jsp
Generated servlet error:
InputStream cannot be resolved to a type

An error occurred at line: 7 in the jsp file: /ProcessFileUpload.jsp
Generated servlet error:
StreamUtil cannot be resolved

org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:512)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:377)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)

root cause

org.apache.jasper.JasperException: Unable to compile class for JSP

An error occurred at line: 7 in the jsp file: /ProcessFileUpload.jsp
Generated servlet error:
ServletFileUpload cannot be resolved to a type

An error occurred at line: 7 in the jsp file: /ProcessFileUpload.jsp
Generated servlet error:
ServletFileUpload cannot be resolved to a type

An error occurred at line: 7 in the jsp file: /ProcessFileUpload.jsp
Generated servlet error:
FileItemIterator cannot be resolved to a type

An error occurred at line: 7 in the jsp file: /ProcessFileUpload.jsp
Generated servlet error:
FileItemStream cannot be resolved to a type

An error occurred at line: 7 in the jsp file: /ProcessFileUpload.jsp
Generated servlet error:
InputStream cannot be resolved to a type

An error occurred at line: 7 in the jsp file: /ProcessFileUpload.jsp
Generated servlet error:
StreamUtil cannot be resolved

org.apache.jasper.compiler.DefaultErrorHandler.javacError(DefaultErrorHandler.java:84)
org.apache.jasper.compiler.ErrorDispatcher.javacError(ErrorDispatcher.java:328)
org.apache.jasper.compiler.JDTCompiler.generateClass(JDTCompiler.java:414)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:297)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:276)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:264)
org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:563)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:305)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)

My HTML:

<HTML>
  <HEAD>
    <META HTTP-EQUIV="Content-Type" CONTENT="text/html; charset=windows-1252"/>
    <TITLE>File Upload Page</TITLE>
  </HEAD>
  <BODY>Upload Files
    <FORM name="filesForm" action="ProcessFileUpload.jsp"
    method="post" enctype="multipart/form-data">
        File 1:<input type="file" name="file1"/><br/>
        File 2:<input type="file" name="file2"/><br/>
        File 3:<input type="file" name="file3"/><br/>
        <input type="submit" name="Submit" value="Upload Files"/>
    </FORM>
  </BODY>
</HTML>
My final JSP which uploads is:
<%@ page import="org.apache.commons.fileupload.*,org.apache.commons.fileupload.*,java.util.List,java.util.Iteratorjava.io.*"%>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=windows-1252">
<title>Process File Upload</title>
</head>
<%        // Create a new file upload handler
ServletFileUpload upload = new ServletFileUpload();
 
// Parse the request
FileItemIterator iter = upload.getItemIterator(request);
while (iter.hasNext()) {
    FileItemStream item = iter.next();
    String name = item.getFieldName();
    InputStream stream = item.openStream();
    if (item.isFormField()) {
        System.out.println("Form field " + name + " with value "
            + StreamUtil.asString(stream) + " detected.");
    } else {
        System.out.println("File field " + name + " with file name "
            + item.getName() + " detected.");
        // Process the input stream
        
    }
}
%>
<body>
Upload Successful!!
</body>
</html>

[BPSouther: Added UBB Code tags]
[ November 28, 2006: Message edited by: Ben Souther ]

ServletFileUpload is in package org.apache.commons.fileupload.servlet, which is not imported (org.apache.commons.fileupload is imported twice).

The other missing classes are not part of Commons FileUpload API, AFAICT, and need to be imported as well.

The import statement is also missing a comma at "java.util.Iteratorjava.io.*".

My advice would be to handle file uploads in a servlet, not a JSP. It will be much easier to handle the upload logic and error cases, and then dispatch to one or more JSP pages depending on the outcome.
[ November 27, 2006: Message edited by: Ulf Dittmer ]

Try with these code;

HTML-->>
<form method="post" action="fileUpload.jsp" name="upform" enctype="multipart/form-data">
  <table width="60%" border="0" cellspacing="1" cellpadding="1" align="center" class="style1">
    <tr>
      <td align="left"><b>Select a file to upload :</b></td>
    </tr>
    <tr>
      <td align="left">
        <input type="file" name="uploadfile" size="50">
        </td>
    </tr>
    <tr>
      <td align="left">
  <input type="hidden" name="todo" value="upload">
        <input type="submit" name="Submit" value="Upload">
        <input type="reset" name="Reset" value="Cancel">
      </td>
    </tr>
  </table>
</form>
</body>
</html>
<<------------------------>>
JSP -->>
<%@ page import="java.io.*,javax.servlet.http.HttpServletRequest,javax.servlet.ServletInputStream" %>
<%@ page import="java.io.FileWriter,java.io.IOException" %>
<%
 String savePath = "", filepath = "", filename = "";
 String contentType = "", fileData = "", strLocalFileName = "";
 int startPos = 0;
 int endPos = 0;
%>
<%!
 //copy specified number of bytes from main data buffer to temp data buffer
 void copyByte(byte[] fromBytes, byte[] toBytes, int start, int len)
 {
for(int i=start;i<(start+len);i++)
  {
   toBytes[i-start] = fromBytes[i];
  }
 }
%>
<%
 int BOF = 0, EOF = 0;
 contentType = request.getContentType();
 out.println("<br>Content type is :: " +contentType);
 if((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0))
 {
  DataInputStream in = new DataInputStream(request.getInputStream());
  DataInputStream in1 = in;
  int formDataLength = request.getContentLength();
  byte dataBytes[] = new byte[formDataLength];
  int byteRead = 0;
  int totalBytesRead = 0;
  while (totalBytesRead < formDataLength)
  {
   byteRead = in1.read(dataBytes, totalBytesRead, formDataLength);
   totalBytesRead += byteRead;
  }
  out.println("<br>totalBytesRead : " + totalBytesRead + " :formDataLength = " + formDataLength);
  //String file = new String(dataBytes);
  //out.println("<br>FileContents:<br>////////////////////////////////////<br>" + file + "<br>////////////////////////////////<br>");
 
  byte[] line = new byte[128];
  if (totalBytesRead < 3)
  {
    return; //exit if file length is not sufficiently large
  }
 
String boundary = "";
String s = "";
int count = 0;
int pos = 0;
 
  //loop for extracting boundry of file
  //could also be extracted from request.getContentType()
  do
  {
   copyByte(dataBytes, line, count ,1); //read 1 byte at a time
   count+=1;
   s = new String(line, 0, 1);
   fileData = fileData + s;
   pos = fileData.indexOf("Content-Disposition: form-data; name=\""); //set the file name
   if(pos != -1)
    endPos = pos;
  }while(pos == -1);
  boundary = fileData.substring(startPos, endPos);
 
  //loop for extracting filename
  startPos = endPos;
  do
  {
   copyByte(dataBytes, line, count ,1); //read 1 byte at a time
   count+=1;
   s = new String(line, 0, 1);
   fileData = fileData + s;
   pos = fileData.indexOf("filename=\"", startPos); //set the file name
   if(pos != -1)
    startPos = pos;
  }while(pos == -1);
  do
  {
   copyByte(dataBytes, line, count ,1); //read 1 byte at a time
   count+=1;
   s = new String(line, 0, 1);
   fileData = fileData + s;
   pos = fileData.indexOf("Content-Type: ", startPos);
   if(pos != -1)
    endPos = pos;
  }while(pos == -1);
  filename = fileData.substring(startPos + 10, endPos - 3); //to eliminate " from start & end
  strLocalFileName = filename;
  int index = filename.lastIndexOf("\\");
  if(index != -1)
   filename = filename.substring(index + 1);
  else
   filename = filename;
 
  //loop for extracting ContentType
  boolean blnNewlnFlag = false;
  startPos = endPos; //added length of "Content-Type: "
  do
  {
   copyByte(dataBytes, line, count ,1); //read 1 byte at a time
   count+=1;
   s = new String(line, 0, 1);
   fileData = fileData + s;
   pos = fileData.indexOf("\n", startPos);
   if(pos != -1)
   {
    if(blnNewlnFlag == true)
     endPos = pos;
    else
    {
     blnNewlnFlag = true;
     pos = -1;
    }
   }
  }while(pos == -1);
  contentType = fileData.substring(startPos + 14, endPos);
 
  //loop for extracting actual file data (any type of file)
  startPos = count + 1;
  do
  {
   copyByte(dataBytes, line, count ,1); //read 1 byte at a time
   count+=1;
   s = new String(line, 0, 1);
   fileData = fileData + s;
   pos = fileData.indexOf(boundary, startPos); //check for end of file data i.e boundry value
  }while(pos == -1);
  endPos = count - boundary.length();
  //file data extracted
 
out.println("<br><br>0. Local File Name = " + strLocalFileName);
out.println("<br><br>1. filename = " + filename);
out.println("<br>2. contentType = " + contentType);
out.println("<br>3. startPos = " + startPos);
out.println("<br>4. endPos = " + endPos);
out.println("<br>5. boundary = " + boundary);
 
  //create destination path & save file there
  String appPath = application.getRealPath("/");
  out.println("<br>appPath : " + appPath);
  String destFolder = appPath + "uploaded/";
  filename= destFolder + filename;
  FileOutputStream fileOut = new FileOutputStream(filename);
  fileOut.write(dataBytes, startPos, (endPos - startPos));
  fileOut.flush();
  fileOut.close();
  out.println("<br>File saved as >> " + filename);
  //file saved at destination
  //out.println("<br>File data : <br><br>**************************<br>" + (new String(dataBytes,startPos, (endPos - startPos))) + "<br><br>**************************");
 }
 else
 {
  out.println("Error in uploading ");
 }
 
%>
<<---------------------------------------------->>

[BPSouther: Added UBB CODE tags]
[ November 28, 2006: Message edited by: Ben Souther ]

Hai error message for the above code:
HTTP Status 404 - d:\Program Files\Apache Software Foundation\Tomcat 5.5\webapps\ROOT\uploaded\new.xml (The system cannot find the path specified)

it is working fine ppl
i have created a folder to put the file

One more thing pandya
Can i upload zip file using the above code.....
Any ideas and suggestions please provide me.....

Hey jothish,
as far as i tested it... it will work for any kind of file.
.doc, .xls, .zip. etc...
if you have any problem do contact me regarding it.

Kaushal Pandya,

Javaranch tip:

If you are going to post more than a line or two of your code, wrap that
code in a set of UBB Code tags.
Doing so will help to preserve your code's indenting, making it easier to read.
If it is easier to read, more people will actaully read it and you will
stand a better chance of getting help with your question.
See UseCodeTags for more
help with UBB code tags.

Thanks Ben,
will keep this in mind.
thank you once again.

Ppl,
One more thing downloading a csv file from server i am facing a problem...
My pice of code to throw output to browser
Is this the way to do this....?

For the above code i am getting the output stream from browser not the expected one it is throwing with error message stating couldn't read the file