This is an ORACLE SQL question, rather than a JDBC question. Suppose i have a table 'Table1' with the following records:
Fund :Col2: SeqNo: Col4 ======================== 1 1 1 x 1 1 2 y 2 1 5 y 2 1 6 x 1 0 3 p 2 0 4 y
The Query that would return this resultset in the order given above is: Select * from table1 order by Col2 desc,SeqNo asc. My question is how do i define a Cursor in my stored proc such that i get the last 2 (n in general) rows in the example specific above. i.e How do i define a cursor such that i get the records with the lowest Col2 (for a Fund) and the highest SeqNo for this lowest Col2 (for the fund). Please note that the record for a given Fund with the lowest Col2 may not have the highest SeqNo for the Fund (as in Record#6 and Record#4 in the example).
Please give the Query for the cursor.
posted 8 years ago
Oracle has some excellent analytical functions which solves your question.
Here is the query for your dataset. But you can change it to get any desired results. For more information analytical functions take a look Oracle Data warehousing guide
The above query gives least col2 record (and max seq within the least col2) for each fund. If you need the least col2 across fund you need to change the over() clause.