These methods are making comparison between 2 objects based on their properties. I would like to achieve the same thing in an identical compound class (@IdClass) based on at least 4 or more properties. ie firstname, surname, dob and sex.
Joined: Oct 20, 2006
Could anyone provide some suggestion on how this could be done?
Jack, There's nothing EJB specific about these methods. They are just normal Java equals() and hashCode() methods. Note that EqualsBuilder provides dynamic implementations so you don't have to write your own.
I don't like the looks of "if (obj == this) return true;" inside of equals() method, it seems like a bad idea.
Other than that, this really is not an EJB issue, its more of a general java question, so I'm moving it to Java Intermediate. You should read up on equals() methods. Usually in a database environment you have a unique primary key (String, Integer, or Long) that unique determines the object. [ May 29, 2008: Message edited by: Scott Selikoff ]