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Joined: May 15, 2008
Oct 19, 2008 20:26:00
I want to create a named query, which will return all the names which starts with "ABC", similar to the query below:
select * from customer where name like 'ABC%'
or, if i the
'ABC' is stored in a variable, than above query becomes:
select * from customer where name like name+'%'
I write a named query like this:
select c from customer c where name like :name
its working, but its not waht i want, when i changed the above named query to below:
select c from customer c where name like :name%
Above query gives exception. How to do such thing?
Joined: Nov 24, 2005
Oct 19, 2008 21:56:00
You don't want to append the '%' directly to the name variable, when calling setParameter ?
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I agree. Here's the link:
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