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HTTPS Post Request through the URL
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Amitabh Sinha
Greenhorn
Joined: Sep 02, 2004
Posts: 1
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posted

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Hi Guys When I try sending the https post request through the java program String param = "https://abcdefg.com"; URL url = new URL(param); HttpsURLConnection httpConnection = (HttpsURLConnection)url.openConnection(); jrunCookie = httpConnection.getHeaderField("set-cookie"); httpConnection.setUseCaches(false); httpConnection.setRequestProperty("Content-Type","application/x-www-form-urlencoded"); httpConnection.setRequestProperty("referer", param); HttpsURLConnection.setFollowRedirects(false); httpConnection.setInstanceFollowRedirects(false); httpConnection.setDoInput(true); httpConnection.setDoOutput(true); httpConnection.setRequestMethod("POST"); it throws the exception and exception reads as URL is not correct. it should be abcdef.com Could sanyone help me with the code forthis perpose.
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Pat Hays
Ranch Hand
Joined: Aug 20, 2004
Posts: 138
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posted

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have a look the following code, it may be helpful for you. Sending a POST Request Using a Socket. try { // Construct data String data = URLEncoder.encode("key1", "UTF-8") + "=" + URLEncoder.encode("value1", "UTF-8"); data += "&" + URLEncoder.encode("key2", "UTF-8") + "=" + URLEncoder.encode("value2", "UTF-8"); // Send data URL url = new URL("http://hostname:80/cgi"); URLConnection conn = url.openConnection(); conn.setDoOutput(true); OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream()); wr.write(data); wr.flush(); // Get the response BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream())); String line; while ((line = rd.readLine()) != null) { // Process line... } wr.close(); rd.close(); } catch (Exception e) { }
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subject: HTTPS Post Request through the URL
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