SimpleDateFormat

[Janne ukko]

Hello need some help !

i take in a String that looks like timePattern

I just wonder how i change the output format when converting this


if i make a print out on the result now i got Thu Nov 25 00:00:00 CET 2004
if i want for example 2004-11-30 12:33:35 how do i do that.


String timePattern = "yyyy-MM-dd";
SimpleDateFormat formatter = new SimpleDateFormat(timePattern);

Date fe=getDateInstance(formatter);

Date d = null;
try {
d = formatter.parse(publishDate, new ParsePosition(0));
} catch (NullPointerException e) {
}
System.out.print(d) // gives Thu Nov 25 00:00:00 CET 2004

[Paul Sturrock]

You are printing out the Date object, not the SimpleDateFormat object.

[Janne ukko]

but i want the correct date into the Date varible to send to a function that set a Date varible, how do i do that

[Simon Birch]

The Date object contains an internal representation of the date, so it will have the correct value, regardless of the format you use to enter the date.

For example

import java.util.Date;
import java.text.SimpleDateFormat;
 
public class DateSample {
public static void main(String[] args) {
Date d = new Date();
SimpleDateFormat df = new SimpleDateFormat();

df.applyPattern("yyyy-MM-dd");
System.out.println(df.format(d));

df.applyPattern("dd MMM yyyy");
System.out.println(df.format(d));

df.applyPattern("E, dd MMMM, yyyy");
System.out.println(df.format(d));
}
}

Also, have a look at the Sun API Docs