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get fifth element from last linked list
Joined: Feb 15, 2005
Sep 26, 2007 11:35:00
Could anyone help me with a method for a Singly Linked List which gets fifth element from last linked list
I have the logic here:
1) have two ptrs. F_Ptr & S_Ptr.
2) Let the ptrs point to the START.
3) Take n as the offset.
4) Start traversing the S_Ptr after the F_Ptr after n.
suppose you want to find 5 element from the last of the list.
In the above case.
1) n = 5 // 5th element from the last
2) check atleast this many elements are there in the list before beginging
// traverse the F_Ptr offset for(;n!=0;n�,F_Ptr->next); // now set the S_Ptr to trail the F_Ptr S_Ptr = F_Ptr; for(;F_Ptr!=NULL; S_Ptr=F_Ptr; F_Ptr=F_Ptr->next) Now whe F_Ptr = Null, S_Ptr is just trailing behind right! it will be pointing to the n�th element from the last. When F_Ptr reaches end (i.e., F_Ptr is NULL) S_Ptr points to the 5th element from the last.
Joined: Oct 29, 2001
Sep 26, 2007 11:41:00
Please do not post
the same question
more than once. It causes confusion and duplication of effort as the community tries to help everyone.
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I agree. Here's the link:
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