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Hi, I have the foll. settings. OS:windowsNT. Java on d:\jdk1.2 Tomcat on d:\tomcat My batch file:- SET CLASSPATH=d:\tomcat\lib\servlet.jar;d:\oracle\ora81\jdbc\lib\classes111.zip; SET JAVA_HOME=d:\jdk1.2; SET TOMCAT_HOME=d:\tomcat; PATH is set to d:\jdk1.2\bin; I run my batch file and type tomcat start, I get the message 'Unable to locate servlet.jar,check value of TOMCAT_HOME'. One copy of servlet.jar is in lib directory. I have not changed startup.bat and tomcat.bat files. I have checked all relevant posts. Any help appreciated. Thanks, Ajay.
First: you do not need the semicolons at the end of each setting Second: you run on WinNT, do you execute your batch before you run tomcat? For each DOS window opened you might have to execute the bat file. If you would set these settings within the system then it would be set for any window you open. PATH=%JAVA_HOME%\bin;%TOMCAT_HOME%
Joined: Apr 18, 2001
It seems to work after I remove the semicolon. Thanks CM.