how to extract the API class files from a jar file. When we download the API of servlet it comes in a jar file. I don't know how to extract it and install it. Thanks in advance.
David Freels
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To extract all files in a jar, use this command jar xvf jarname.jar. Use jar -help for more options. David
shabbir zakir
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tahnks David. but when i use to extract the servlet.jar with the above option it is giving me error that java.io.FileNotFoundException(Access denied). how to solve this error.
babukumar
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hi just use winzip to unzip a jar file if u dont know how to unzip using jar command prompt and options. naren.
shabbir zakir
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HI NAREN!
THANKS FOR YOUR REPLY. BUT ACCORDING TO MY KNOWLEDGE WINZIP IS USED TO UNZIP A FILE NOT A JAR FILE.
David Freels
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Originally posted by shabbir zakir: HI NAREN!
THANKS FOR YOUR REPLY. BUT ACCORDING TO MY KNOWLEDGE WINZIP IS USED TO UNZIP A FILE NOT A JAR FILE.
Winzip can unzip jar files. A jar file is just a mutant hybrid between a tar file and a zip file. Winzip can also open tar files. David Sun Certified Programmer for the Java2 Platform
Phil Hanna
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You don't need to unzip servlet.jar to use the class files it contains. The class path just needs "servlet.jar" in it. ------------------ Phil Hanna Author of : JSP: The Complete Reference Instant Java Servlets
Phil Hanna<BR>Sun Certified Programmer for the Java 2 Platform<BR>Author of :<BR><A HREF="http://www.amazon.com/exec/obidos/ASIN/0072127686/electricporkchop/107-3548162-1137317" TARGET=_blank rel="nofollow">JSP: The Complete Reference</A><BR><A HREF="http://www.amazon.com/exec/obidos/ASIN/0072124253/electricporkchop/107-3548162-1137317" TARGET=_blank rel="nofollow">Instant Java Servlets</A>