input type = file problem

[saravanan balakrishnan]

hi,
i'm using <input type="file" name="filename1"> in my jsp.when i was trying to get the parameter in my servlet using getParameter method,i'm getting only null.why is it?
can u give me some solution for this.
thanx

[Metal God]

Hi Bala
Precisely what you wanted to retrieve? do you want to retrieve a file contents or the filename?
MG

[phongtran]

Hi Bala
Because <input type="file" name="filename1"> is used only for MultiPart form.
So that you must use multipart.getParammter()
About MultiPart, please contact him
// Copyright (C) 1998 by Jason Hunter <[e-mail]>. All rights reserved.
// Use of this class is limited. Please see the LICENSE for more information.
OR, you can download some java class (package cos.jar)
com.oreilly.servlet.multipart.MultipartParser;
com.oreilly.servlet.multipart.Part;
com.oreilly.servlet.multipart.FilePart;
com.oreilly.servlet.multipart.ParamPart;

Bye
Quoc Phong

[saravanan balakrishnan]

hi,
thanx guys for the reply.
i need the filename(from my local system,for example,C:\com\) to my servlet.is there any other method other than Multipart?
thanx

[phongtran]

Hi
You can to use hidden field in your form
When you submit, you use JavaScript to get your fileName
And then, in your servlet, you must use mutilPart.getParameter() to get your fileName
Example:
In your HTML file
<FORM NAME="UploadFile" ACTION="" ENCTYPE="multipart/form-data" METHOD=POST>
<input type="FILE" name="file" value="">
<input type="hidden" name="fileName" value="">
</FORM>
<script language="JavaScript">
function onSubmit() {
fileName.value = file.value;
}
</script>
In your Servlet file
fileName = multiPart.getParameter("fileName");
Have fun, this is my idea, ;-)
Quoc Phong